In the constant current excitation, the voltage drop that flows through the inductor , the voltage as the frequency increases. An active device can be used as an inductor, and its output as the frequency increases. This circuit and the effective inductance (L = R1R2C) to produce a feedback. The Q of the inductor depends on the R1 equal to R2,. At the same time, the forward and reverse feedback path of the amplifier are the same.
Comes from http://www.hqew.net/circuit-diagram/Simulated-Inductor-Circuit_2255.html
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